f(x)=(cosx)^2/[sinxcosx- (sinx)^2]
=(cosx)^2/[sinxcosx+(cosx)^2-1]
=1/[tgx+1-(secx)^2]
=1/{tgx+1-[1+(tgx)^2]}
=1/[tgx-(tgx)^2]
=1/[-(tgx-1/2)^2+1/4]
>=1/[0+1/4]
=4,當(dāng)且僅當(dāng)tgx=1/2時取等,此時x=arctg(1/2)