Mg+2HCl═MgCl2+H2↑,
24 73 95 2
24g x y z
24 |
24g |
73 |
x |
95 |
y |
2 |
z |
x=73g,y=95g,z=2g,
反應(yīng)后得到不飽和溶液的質(zhì)量為:95g÷25%=380g,
設(shè)稀鹽酸的質(zhì)量為m,根據(jù)題意有:24g+m-2g=380g,
m=358g,
所用鹽酸中溶質(zhì)的質(zhì)量分?jǐn)?shù)為:
73g |
358g |
答:所用鹽酸中溶質(zhì)的質(zhì)量分?jǐn)?shù)為20.4%.