∵x^2+y^2=10,x+xy+y=7
∴ 7-xy=x+y,且2xy≤x^2+y^2=10,
∴(7-xy)^2=(x+y)^2=x^2+y^2+2xy=10+2xy,且xy≤5
∴49-14xy+(xy)^2=10+2xy,即(xy)^2-16xy+39=0,解得xy=3或xy=13(舍去)
∴x=3/y,代入x^2+y^2=10并整理得y^4-10y^2+9=0,解得y=1或y=-1或y=3或y=-3
∴當(dāng)y=1時(shí),x=3,當(dāng)y=-1時(shí),x=-3,當(dāng)y=3時(shí),x=1,當(dāng)y=-3時(shí),x=-1