｛28x+18y=1①{30y+20x=1②由②得3y+2x=0.12x=0.1-3y③將③代入①1.4-52y+18y=11.4+34y=134y=0.434y=2/5y=2/5*1/34x=1/60將x=1/60代入③1/30=0.1-3y1/30=1/10-3y1/30-1/10=3y1/30-3/30=3y-1/15=3yy=-45x=1/60,y=-45...再求解一個(gè)：3√2x+√3y=6√2—2√6和2x-(√2-√6)y=2不好意思啊，“√”是根號(hào)，不知道怎么打~(⊙o⊙)…原諒我吧，我一定選你為滿意答案的！求你了~~~~(>_<)~~~~1式*根號(hào)(2)得：6x - 根號(hào)(6)y = 12 - 4根號(hào)(3)-----3式； 2式*3得：6x + (3根號(hào)(6) - 3根號(hào)(2))y = 6------4式； 3式 - 4式得：(3根號(hào)(2) - 4根號(hào)(6))* y = 6 - 4根號(hào)(3); 解之得：y = (6 - 4根號(hào)(3))/(3根號(hào)(2) - 4根號(hào)(6))= (6 - 4根號(hào)(3))*(3根號(hào)(2)+4根號(hào)(6))/((3根號(hào)(2) - 4根號(hào)(6))*(3根號(hào)(2)+4根號(hào)(6)) = -(18根號(hào)(2) + 24根號(hào)(6) - 12根號(hào)(6) - 48根號(hào)(2))/78 = (5根號(hào)(2) - 2根號(hào)(6))/13; 再將y代入2式通分得：26x - 22 + 14根號(hào)(3) = 26=>x = (24 - 7根號(hào)(3))/13;