一、1、(m²-3m+2)-(4m-2n-1)=m²-7m+2n+32、(3x²+4x-1)-3(x²+3x) =-5x-13、- 5(x²-3)-2(3x²+5)=-11x²+54、-(x²y+3xy-4)+3(x²y-xy+2)=2x²y-4xy+105、[(11/2)x²...拜托說下第一大題的過程，， 合并同類項1、(m²-3m+2)-(4m-2n-1)=m²-3m+2-4m+2n+1=m²-(3+4)m+2n+(2+1)=m²-7m+2n+32、(3x²+4x-1)-3(x²+3x) =3x²+4x-1-3x²-9x=-5x-13、- 5(x²-3)-2(3x²+5)=- 5x²+15-6x²-10=-11x²+54、-(x²y+3xy-4)+3(x²y-xy+2)=-x²y-3xy+4+3x²y+3xy+6=2x²y+105、[(11/2)x²-29x+10y]-[(5/2)x²-13x+24y] =(11/2)x²-29x+10y-(5/2)x²+13x-24y=3x²-16x-14y6、- (1/4)(2k³+4k²-28)+(1/2)(k³-2k²+4k) =- (1/2)k³-k²+7+(1/2)k³-k²+2k)=-2k²+2k+7以這次的為準(zhǔn)吧，上面還真有錯的三角的第二問不太清楚