1,求M的值
y=log{[1-m(x-2)]/(x-3)}
當x=0時,y=log[(1+2m)/(-3)]
當x=4時,y=log(1-2m)
已知其圖像關(guān)于x=2對稱,則：f(0)=f(4)
即：log[(1+2m)/(-3)]=log(1-2m)
===> (1+2m)/(-3)=1-2m
===> 1+2m=-3+6m
===> m=1
2 由(1)知,m=1
所以,y=log[(3-x)/(x-3)]————?!