x/(x+3)-(x+1)/(x-2)=(x-2m)/(x^2+x-6)
x/(x+3)-(x+1)/(x-2)=(x-2m)/[(x-2)(x+3)]
同時乘以(x-2)(x+3),得
x(x-2)-(x+1)(x+3)=x-2m
x^2-2x-(x^2+4x+3)=x-2m
x^2-2x-x^2-4x-3=x-2m
-6x-3=x-2m
-7x=3-2m
7x=2m-3
x=(2m-3)/7
解不小于1,即
(2m-3)/7≥1
2m-3≥7
m≥5
當m≥5時,分式方程x+3分之x減去x-2分之x+1=x的平方+x-6分之x-2m的解不小于1