①函數(shù)y=√cos(2x-π/3)的導(dǎo)數(shù)怎么求,②函數(shù)y=cos^31/x的導(dǎo)數(shù),
①函數(shù)y=√cos(2x-π/3)的導(dǎo)數(shù)怎么求,②函數(shù)y=cos^31/x的導(dǎo)數(shù),
數(shù)學(xué)人氣：107 ℃時(shí)間：2019-12-20 19:44:30
優(yōu)質(zhì)解答
1.將cos(2x-π/3)看成整體√cos(2x-π/3)的導(dǎo)數(shù)是1/[2√cos(2x-π/3)]將2x-π/3看成整體cos(2x-π/3)的導(dǎo)數(shù)是-sin(2x-π/3)2x-π/3的導(dǎo)數(shù)是2根據(jù)復(fù)合函數(shù)求導(dǎo)的原理y'=1/[2√cos(2x-π/3)]*[-sin(2x-π/3)]*2=-sin(2...第二個(gè)函數(shù)為cos^3(1/x)道理一樣的，先將cos1/x看成整體，導(dǎo)數(shù)是3cos^2(1/x)將1/x看成整體cos1/x的導(dǎo)數(shù)是-sin1/x1/x的導(dǎo)數(shù)是-1/x^2所以y'=3cos^2(1/x)*(-sin1/x)*(-1/x^2)=[3cos^2(1/x)*sin1/x]/x^2
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