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    [2/xy/(1/x+1/y)2+(x2+y2)/(x2+2xy+y2)]*2x/(x-y)
    

    [2/xy/(1/x+1/y)2+(x2+y2)/(x2+2xy+y2)]*2x/(x-y)
    

    數(shù)學(xué)人氣：130 ℃時(shí)間：2020-05-14 17:23:24
    

    優(yōu)質(zhì)解答
    

    [2/xy/(1/x+1/y)²+(x²+y²)/(x²+2xy+y²)]*2x/(x-y)
    =[2/xy/(x+y)²/x²y²+(x²+y²)/(x+y)²]*2x/(x-y)
    =[2xy/(x+y)²+(x²+y²)/(x+y)²]*2x/(x-y)
    =[(2xy+x²+y²)/(x+y)²]*2x/(x-y)
    =(x+y)²/(x+y)²*2x/(x-y)
    =2x/(x-y)
    

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