73g*10%=7.3g
設(shè)碳酸鈉的質(zhì)量為x 則碳酸氫鈉的質(zhì)量為 9.3g-x
Na2CO3+2HCl==2NaCl+H2O+CO2↑
106 73 44
x 73x/106 44x/106
NaHCO3+HCl==NaCl+H2O+CO2↑
84 36.5 44
9.3g-x 36.5*(9.3g-x)/84 44*(9.3g-x)/84
73x/106+36.5*(9.3g-x)/84=7.3g
x=
題目數(shù)據(jù)有問題呀= =我不是補充說了是氫氧化鈉和碳酸鈉么。。。NaOH+HCl=NaCl+H2O4036.59.3g-x 36.5*(9.3g-x)/4073x/106+36.5*(9.3g-x)/40=7.3gx=5.3g二氧化碳的質(zhì)量為44x/106=44*5.3/106=2.2g氯化鈉的質(zhì)量為HCl------NaCl36.5 58.57.3gm=11.7g反映后所得溶液中溶質(zhì)的質(zhì)量分數(shù) 11.7g/(73g+9.3g-2.2g)*100%=14.6%。