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  • (1)已知x=1/2+根號(hào)3,xy=1,則x^2y-xy^2/x^2-y^2=_____.

    (1)已知x=1/2+根號(hào)3,xy=1,則x^2y-xy^2/x^2-y^2=_____.
    (2)化簡(jiǎn)1+2根號(hào)3+根號(hào)5/(1+根號(hào)3)(根號(hào)3+根號(hào)5)=______.
    (3)已知x=根號(hào)3+1,y=根號(hào)3-1,則x^2-2xy+y^2/x^2-y^2=______.
    (4)已知a+1/a=5,則a^4+a^2+1/a^2=_____.
    數(shù)學(xué)人氣:682 ℃時(shí)間:2019-11-04 13:11:31
    優(yōu)質(zhì)解答
    (1)已知x=1/2+根號(hào)3=2-√3,xy=1,
    y=2+√3;
    則x^2y-xy^2/x^2-y^2
    =xy(x-y)/(x+y)(x-y)
    =xy/(x+y)
    =1/(2+√3+2-√3)
    =1/4;
    (2)化簡(jiǎn)1+2根號(hào)3+根號(hào)5/(1+根號(hào)3)(根號(hào)3+根號(hào)5)
    =(1+2√3+√5)(√3-1)/(√5+√3)(√3+1)(√3-1)
    =(√3-1+6-2√3+√15-√5)/2(√5+√3)
    =(√15+5-√5-√3)(√5-√3)/2(√5+√3)(√5-√3)
    =(5√3-3√5+5√5-5√3-5+√15-√15+3)/4;
    =(2√5+3)/4;
    (3)已知x=根號(hào)3+1,y=根號(hào)3-1,則x^2-2xy+y^2/x^2-y^2
    =(x-y)²/(x+y)(x-y)
    =(x-y)/(x+y)
    =(√3+1-√3+1)/(√3+1+√3-1)
    =2/2√3
    =√3/3;
    (4)已知a+1/a=5,則a^4+a^2+1/a^2
    =a²+1+1/a²
    =(a+1/a)²-1;
    =5²-1
    =24;
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