概率論：已知P(AUB)=0.8,P(A)=0.5,P(B)=0.6 求P(A逆UB逆)

數(shù)學(xué)人氣：152 ℃時(shí)間：2020-10-01 03:18:41

優(yōu)質(zhì)解答

P(A∩B)=P(AB)=P(A)+P(B)-P(AUB)=0.5+0.6-0.8=0.3
P(A逆)=1-P(A)=0.5
P(B逆)=1-P(B)=0.4
P(A逆∩B逆)=1-P(AUB)=0.2
P(A逆∪B逆)=P(A逆)+P(B逆)-P(A逆∩B逆)
=0.5+0.4-0.2
=0.7P(A逆UB逆)=1-P（AB）吧？對(duì)哦這樣也行呢P(A逆UB逆)=1-P（AB）=1-0.3=0.7請(qǐng)問下：A,B為互不相容的隨機(jī)事件,則P(AUB)=P(A)+P(B)和P(AB)=P(A)P(B)哪個(gè)對(duì)互不相容的話 P(AB)=0那么P(AUB)=P(A)+P(B)