∴(2a+1)+(2b+1)=4,2a+1>0,2b+1>0
則
1 |
2a+1 |
4 |
2b+1 |
1 |
4 |
1 |
2a+1 |
4 |
2b+1 |
=
1 |
4 |
2b+1 |
2a+1 |
4(2a+1) |
2b+1 |
≥
1 |
4 |
|
9 |
4 |
當(dāng)且僅當(dāng)
2b+1 |
2a+1 |
4(2a+1) |
2b+1 |
1 |
6 |
5 |
6 |
∴
1 |
2a+1 |
4 |
2b+1 |
9 |
4 |
1 |
2a+1 |
4 |
2b+1 |
9 |
4 |
1 |
2a+1 |
4 |
2b+1 |
1 |
4 |
1 |
2a+1 |
4 |
2b+1 |
1 |
4 |
2b+1 |
2a+1 |
4(2a+1) |
2b+1 |
1 |
4 |
|
9 |
4 |
2b+1 |
2a+1 |
4(2a+1) |
2b+1 |
1 |
6 |
5 |
6 |
1 |
2a+1 |
4 |
2b+1 |
9 |
4 |