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  • (sin5π/12+cos5π/12)(sinπ/12-cosπ/12)

    (sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
    數(shù)學(xué)人氣:350 ℃時(shí)間:2020-04-14 11:10:50
    優(yōu)質(zhì)解答
    (sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
    =[sin(π/2-π/12)+cos(π/2-π/12)](sinπ/12-cosπ/12)
    =(cosπ/12+sinπ/12)(sinπ/12-cosπ/12)
    =sin²π/12-cos²π/12
    =-(cos²π/12-sin²π/12)
    =-cosπ/6
    =-√3/2
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