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  • 分解因式: (1)(2x2-3x+1)2-22x2+33x-1; (2)x4+7x3+14x2+7x+1; (3)(x+y)3+2xy(1-x-y)-1; (4)(x+3)(x2-1)(x+5)-20.

    分解因式:
    (1)(2x2-3x+1)2-22x2+33x-1;
    (2)x4+7x3+14x2+7x+1;
    (3)(x+y)3+2xy(1-x-y)-1;
    (4)(x+3)(x2-1)(x+5)-20.
    數(shù)學(xué)人氣:321 ℃時間:2020-05-12 02:44:18
    優(yōu)質(zhì)解答
    (1)(2x2-3x+1)2-22x2+33x-1,
    =(2x2-3x+1)2-11(2x2-3x+1)+10,
    =(2x2-3x+1-1)(2x2-3x+1-10),
    =(2x2-3x)(2x2-3x-9),
    =x(2x-3)(2x+3)(x-3);
    (2)x4+7x3+14x2+7x+1,
    =x4+4x3+6x2+4x+1+3x3+6x2+3x+2x2,
    =[(x+1)2]2+3x(x+1)2+2x2,
    =[(x+1)2+2x][(x+1)2+x],
    =(x2+4x+1)(x2+3x+1);
    (3)(x+y)3+2xy(1-x-y)-1
    =[(x+y)3-1]+2xy(1-x-y)
    =(x+y-1)[(x+y)2+x+y+1]-2xy(x+y-1)
    =(x+y-1)(x2+y2+x+y+1);
    (4)(x+3)(x2-1)(x+5)-20,
    =(x+3)(x+1)(x-1)(x+5)-20,
    =(x2+4x+3)(x2+4x-5)-20,
    =(x2+4x)2-2(x2+4x)-15-20,
    =(x2+4x+5)(x2+4x-7).
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