：設(shè)該合金中有鋁a mol,有鎂b mol.
由合金質(zhì)量為5.1g可得：27a+24b=5.1【1】
2Al------3H2 Mg--------H2
2mol 3mol 1mol 1mol
amol 3/2amol bmol bmol
氫氣的總物質(zhì)的量為：5.6L/(22.4L/mol)=0.25mol
所以3/2a+b=0.25【2】
由【1】【2】可以解得a=0.1,b=0.1
(1)Al的質(zhì)量分?jǐn)?shù)=2.7g/5.1g*100%=52.94%3/2a+b=0.25?????????2?????????????????????????????????????? лл?????3a/2+b=2.5????????3/2??a????????????????????????? ?????????ú????????a mol????tb mol?? ?????????5.1g????27a+24b=5.1??1?? 2Al------3H2 Mg--------H2 2mol 3mol 1mol 1mol amol 3a/2mol bmol bmol ?????????????????5.6L/(22.4L/mol)=0.25mol ????3/2a+b=0.25??2?? ?ɡ?1????2????????a=0.1??b=0.1 (1)Al??????????=2.7g/5.1g*100%=52.94%??????????????????????e?????????лл????ú????????a mol????tb mol?? ?????????5.1g????27a+24b=5.1??1?? 2Al------3H2 Mg--------H2 2mol 3mol 1mol 1mol amol 3a/2mol bmol bmol ?????????????????5.6L/(22.4L/mol)=0.25mol ????3a/2+b=0.25??2?? ?ɡ?1????2????????a=0.1??b=0.1 (1)Al??????????=2.7g/5.1g*100%=52.94%?????????????????????????лл