已知tan(x-y)=2,tan(y+π5)=3,則tan(x+π5)=( ?。?A.-2 B.2 C.-1 D.1
已知tan(x-y)=2,tan
(y+)=3,則tan
(x+)=( ?。?br/>A. -2
B. 2
C. -1
D. 1
優(yōu)質(zhì)解答
由tan(x-y)=2,tan
(y+)=3,
則tan(x+
)=tan[(x-y)+(y+
)]=
tan(x-y)+tan(y+) |
1-tan(x-y)tan(y+) |
=
=-1故選C
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