系數(shù)矩陣=
2 -3 -2 1
3 5 4 -2
8 7 6 -3
r2-r1,r3-4r1
2 -3 -2 1
1 8 6 -3
0 19 14 -7
r1-2r2
0 -19 -14 7
1 8 6 -3
0 19 14 -7
r1+r3,r3*(1/19),r2-8r3
0 0 0 0
1 0 2/19 -1/19
0 1 14/19 -7/19
所以方程組的基礎(chǔ)解系為 (2,14,-19,0)^T,(1,7,0,19)^T.不明白從矩陣化完后是如何直接得出基礎(chǔ)解系的,望解答~
求齊次線性方程組的基礎(chǔ)解系2x1-3x2-2x3+x4=0,3x1+5x2+4x3-2x4=0,8x1+7x2+6x3-3x4=0
求齊次線性方程組的基礎(chǔ)解系2x1-3x2-2x3+x4=0,3x1+5x2+4x3-2x4=0,8x1+7x2+6x3-3x4=0
數(shù)學(xué)人氣:364 ℃時(shí)間:2020-05-09 11:52:33
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