在平面直角坐標(biāo)系中,已知點(diǎn)A(4,2),B(4,-3),試在y軸上找一點(diǎn)p,使三角形ABP為等腰三角形,求點(diǎn)P坐標(biāo)
1
以點(diǎn)A為圓心,AB長(zhǎng)為半徑作⊙A,與Y軸有兩個(gè)交點(diǎn):P1(0,5),P2(0,-1);
以點(diǎn)B為圓心,AB長(zhǎng)為半徑作⊙B,與Y軸有兩個(gè)交點(diǎn):P3(0,0),P4(0,-5);
所以,符合條件的點(diǎn)P有4個(gè),分別是P1(0,5),P2(0,-1),P3(0,0),P4(0,-5).
如下圖所示:
![](http://d.hiphotos.baidu.com/zhidao/wh%3D600%2C800/sign=c24202aef403738dde1f0424832b9c69/f9dcd100baa1cd1109c80f2ebb12c8fcc3ce2d45.jpg)