7x≡1(mod11)
設(shè)7x=11*y+1(x,y∈N*)
x=y+(4y+1)/7
設(shè)(4y+1)/7＝m(m∈N*)
y=m+(3m-1)/4
設(shè)(3m-1)/4＝n(n∈N*)
m=n+(n+1)/3
設(shè)(n+1)/3＝t(t∈N*)
n=3t-1
m=3t-1+t=4t-1
y=4t-1+3t-1=7t-2
x=7t-2+4t-1=11t-3(t∈N*)
x=8,19,30,.,11t-3,.(t∈N*)