1)隱函數(shù)求導(dǎo)y'=(2 x)/(x^2 - 2 y + y^2),y在(1,0)上的導(dǎo)數(shù)是2
2)
兩邊關(guān)于x求導(dǎo)得y'=(3 y^2)/(3xy-1)
再求導(dǎo)并把y‘代入得y''=(27 (-y^3 + 2 x y^4))/(-1 + 3 x y)^3?????????????????????????????