若a+b+c=0,abc>0,求a的絕對(duì)值分之b+c + b的絕對(duì)值分之c+a + c的絕對(duì)值分之a(chǎn)+b的值,
若a+b+c=0,abc>0,求a的絕對(duì)值分之b+c + b的絕對(duì)值分之c+a + c的絕對(duì)值分之a(chǎn)+b的值,
數(shù)學(xué)人氣:787 ℃時(shí)間:2019-09-02 09:27:02
優(yōu)質(zhì)解答
原式=(b+c)/|a| + (c+a) /|a| + (a+b)/|c|= -a/|a| - b/|b| - c/|c| = -(a/|a|+ b/|b| + c/|c|)因?yàn)閍+b+c=0,abc>0所以a b c中一定有兩個(gè)是負(fù)數(shù),一個(gè)是正數(shù).所以 a/|a| b/|b| c/|c|中,有一個(gè)是1,兩個(gè)是-1所以 原式...(b+c)/|a| + (c+a) /|a| + (a+b)/|c|= -a/|a| - b/|b| - c/|c|怎么就變這樣了?能解釋一下嗎?我數(shù)學(xué)不太好,看不太懂。謝謝因?yàn)閍+b+c=0;得b+c=-a,a+c=-b,a+b=-c;移項(xiàng)變形就出來(lái)了,明白了沒(méi)?
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