答：
3x²+2(√2-1)x-(3-2√2)=0
3*[x²+2(√2-1)x/3+(√2-1)²/9 ] - (√2-1)²/3-(3-2√2)=0
3*[x+(√2-1)/3]²=(√2-1)²*(1+1/3)
[x+(√2-1)/3]²=(4/9)(√2-1)²
x+(√2-1)/3=±(2/3)(√2-1)
x=[ (√2-1) /3 ]*(-1±2)
x1=(√2-1) /3
x2= 1-√2親，你算錯了吧，(√2-1)²*(1+1/3)是怎么得來的3-2根號2化成平方形式?jīng)]看懂啊，算了，還是謝謝了