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  • 解方程組 4x^2-y=0 3x^2+xy+x-2y+6=0

    解方程組 4x^2-y=0 3x^2+xy+x-2y+6=0
    數(shù)學(xué)人氣:971 ℃時(shí)間:2020-05-19 12:37:34
    優(yōu)質(zhì)解答
    x1 = -1/12*(1261+234*29^(1/2))^(1/3)-13/12/(1261+234*29^(1/2))^(1/3)+5/12
    x2 = 1/24*(1261+234*29^(1/2))^(1/3)+13/24/(1261+234*29^(1/2))^(1/3)+5/12+1/2*i*3^(1/2)*(-1/12*(1261+234*29^(1/2))^(1/3)+13/12/(1261+234*29^(1/2))^(1/3))
    x3 = 1/24*(1261+234*29^(1/2))^(1/3)+13/24/(1261+234*29^(1/2))^(1/3)+5/12-1/2*i*3^(1/2)*(-1/12*(1261+234*29^(1/2))^(1/3)+13/12/(1261+234*29^(1/2))^(1/3))
    x1 = -0.7971
    y1 = 2.5416
    x2 = 1.0236 - 0.9133i
    y2 = 0.8546 - 7.4788i
    x3 = 1.0236 + 0.9133i
    y3 = 0.8546 + 7.4788i
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