據(jù)溶質(zhì)質(zhì)量相等；
設(shè)需要濃硫酸xg;
100×19.6%=x98%;
x=20g;
加入水質(zhì)量=100-20=80g;可不可以求詳細(xì)過程……列方程式解的那樣QAQ設(shè)需要濃硫酸xg; 溶質(zhì)硫酸的質(zhì)量=100×19.6%=x98%;x=20g;加入水的質(zhì)量=后來溶液質(zhì)量-開始溶液質(zhì)量=100-20=80g;