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  • model:title Location problem; sets:demand/1..6/:a,b,d; supply/1,2/:x,y,e; link(demand,supply):c; e

    model:title Location problem; sets:demand/1..6/:a,b,d; supply/1,2/:x,y,e; link(demand,supply):c; e
    照書上寫的,還是出錯了.大惑不解.
    錯誤代碼:50
    for函數使用不當
    所用版本為lingo11
    model:
    title Location problem;
    sets:
    demand/1..6/:a,b,d;
    supply/1,2/:x,y,e;
    link(demand,supply):c;
    endsets
    data:
    a=1.25 8.75 0.5 5.75 3 7.25;
    b=1.25 0.75 4.75 5 6.5 7.75;
    enddata
    init:
    x,y=5,1,2,7;
    endinit
    [obj]min=@SUM( link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i)^2)^(1/2));
    @for(demand(i):@sum(supply(j):c(i,j);)=d(i));
    @for(supply(i):@sum(demand(j):c(j,i);)
    其他人氣:369 ℃時間:2020-05-03 05:19:49
    優(yōu)質解答
    少右括號 model:
    title Location problem;
    sets:
    demand/1..6/:a,b,d;
    supply/1,2/:x,y,e;
    link(demand,supply):c;
    endsets
    data:
    a=1.25 8.75 0.5 5.75 3 7.25;
    b=1.25 0.75 4.75 5 6.5 7.75;
    enddata
    init:
    x,y=5,1,2,7;
    endinit
    [obj]min=@SUM( link(i,j): c(i,j)*((x(j)-a(i))^2+(y(j)-b(i)^2)^(1/2)));
    @for(demand(i): @sum(supply(j):c(i,j);)=d(i));
    @for(supply(i): @sum(demand(j):c(j,i);)@for(supply:@free(X);@free(Y););
    end
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