If positive integer x is a multiple of 6 and positive integer y is a multiple of 14,is xy a multiple of 105?
If positive integer x is a multiple of 6 and positive integer y is a multiple of 14,is xy a multiple of 105?
(1) x is a multiple of 9.
(2) y is a multiple of 25.
A.Statement (1) ALONE is sufficient,but statement (2) alone is not sufficient.
B.Statement (2) ALONE is sufficient,but statement (1) alone is not sufficient.
C.BOTH statements TOGETHER are sufficient,but NEITHER statement ALONE is sufficient.
D.EACH statement ALONE is sufficient.
E.Statements (1) and (2) TOGETHER are NOT sufficient.
The product of the units digit,the tens digit,and the hundreds digit of the positive integer m is 96.What is the units digit of
(1) m is odd.
(2) The hundreds digit of m is 8.
A.Statement (1) ALONE is sufficient,but statement (2) alone is not sufficient.
B.Statement (2) ALONE is sufficient,but statement (1) alone is not sufficient.
C.BOTH statements TOGETHER are sufficient,but NEITHER statement ALONE is sufficient.
D.EACH statement ALONE is sufficient.
E.Statements (1) and (2) TOGETHER are NOT sufficient.
第一題答案是B,第二滴題答案是A,希望寫出向出席步驟,
(1) x is a multiple of 9.
(2) y is a multiple of 25.
A.Statement (1) ALONE is sufficient,but statement (2) alone is not sufficient.
B.Statement (2) ALONE is sufficient,but statement (1) alone is not sufficient.
C.BOTH statements TOGETHER are sufficient,but NEITHER statement ALONE is sufficient.
D.EACH statement ALONE is sufficient.
E.Statements (1) and (2) TOGETHER are NOT sufficient.
The product of the units digit,the tens digit,and the hundreds digit of the positive integer m is 96.What is the units digit of
(1) m is odd.
(2) The hundreds digit of m is 8.
A.Statement (1) ALONE is sufficient,but statement (2) alone is not sufficient.
B.Statement (2) ALONE is sufficient,but statement (1) alone is not sufficient.
C.BOTH statements TOGETHER are sufficient,but NEITHER statement ALONE is sufficient.
D.EACH statement ALONE is sufficient.
E.Statements (1) and (2) TOGETHER are NOT sufficient.
第一題答案是B,第二滴題答案是A,希望寫出向出席步驟,
數(shù)學人氣:749 ℃時間:2020-10-01 21:18:25
優(yōu)質解答
x=6a=2*3*a,y=14b=2*7*b,a、b為正整數(shù),x*y=2*2*3*7*a*b105=3*5*7條件(1)并不能保證x*y是105的整數(shù)倍,條件(2)可以充分滿足x*y是105的整數(shù)倍,所以選B設a、b、c為個位數(shù),依題意有:a*b*c=96=2*2*2*2*2*3,m=100a+10b+c,...
我來回答
類似推薦
- 請高手翻譯兩道gmat數(shù)學題并求解
- One saleman’s salary includes basic salary 6000 and a commission 7% of the week’s sale over 2000,last week and this week
- gmat數(shù)學題
- 15個不同的數(shù)字,都是整數(shù),中位數(shù)25,值域25,最大數(shù)字可能是多少?
- 有一個社區(qū)有四個大學,現(xiàn)要在社區(qū)成立一委員會,委員會由4人組成,二男二女,每個大學提一個名單,包括一男一女,問委員會如從每個大學名單中各取一人,可有多少種取法?
- 求解一道英語語法題
- class seven is having an English class now.改錯
- 我最好的朋友(英語作文)
- 人名迷:1.油煎豆腐(打唐朝一詩人名)
- 口算43+5 先算什么 再算什么
- 1.設f(x)=asin(πx+A)+bcos(πx+B),其中a,b,A,B為非零常數(shù),若f(2009)=-1,則f(2010)= 2.函數(shù)y=2sin(π/6-2x) x屬于【0,π】的單調(diào)遞增區(qū)間是.
- 1、She (usually) helps me with the English. 2、John (sometimes) watches TV. 對()中的部分提問,
猜你喜歡
- 1船速為4m/s,水速為5m/s,則該船能否垂直過河?
- 2小學六年級上學期語文補充習題第20課怎么寫
- 3管線長100米直徑20厘米油密度是0.830算里面多少油
- 4that從句中能不能用主將從現(xiàn).look,see,watch的區(qū)別
- 5一個數(shù)擴大100倍后得到20,這個數(shù)是();把0.5縮小到它的十分之一是()
- 6如圖,已知直線AB和CD相交于點O,∠COE是直角,OF平分∠AOE.寫出∠AOC與∠BOD的大小關系
- 7什么是畫面的張力
- 8一道數(shù)學題火速!要過程,最好講解!
- 9如何用結晶法分離乙醇和水?
- 10用不等式表示"a"與4的差是非負數(shù)
- 11A種飲料每瓶是5分之8升,B種飲料每瓶5分之6升,A種飲料比B種飲料多( )升,多( )百分之幾.
- 12用容量瓶成液體并用玻璃棒引流時,為什么玻璃棒要放在刻度線以下