y=sin^4(x/4)+cos^4(x/4)
=sin^4(x/4)+cos^4(x/4)+2sin^2(x/4)cos^2(x/4)-2sin^2(x/4)cos^2(x/4)
=[sin^2(x/4)+cos^2(x/4)]^2 -1/2 sin^2(x/2)
=1 -1/2 sin^2(x/2)
所以
求導(dǎo),得
y'=-1/2 ×2sin(x/2)×cos(x/2)×1/2
=-1/2sin(x/2)cos(x/2)
=-1/4sinx
求y=sin^4(x/4)+cos^4(x/4)的導(dǎo)數(shù) ,
求y=sin^4(x/4)+cos^4(x/4)的導(dǎo)數(shù) ,
數(shù)學(xué)人氣：530 ℃時(shí)間：2019-12-25 10:01:04
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