∫x sin x²dx= ∫x (1-cos 2x)/2 dx
= ∫x/2 dx - ∫x*cos 2x/2 dx
=x^2/4-1/2*(x*sin2x/2-∫sin 2x/2 dx)
=x^2/4-1/4*x*sin2x - 1/8*cos 2x + C?????y=x ??4?η???2x²??5??????????????????????????????????y=x^4-2x^2-5???????????????ò?????????????????????????????????????????????????????y=x²?????y=2x??Χ???????????????????v?????????x^2??? x??????? ????????y=x²?????y=2x ????0??0????2??2??S=??<0,2>2x-x^2dx=x^2-x^3/3|<0,2>=4-8/3=4/3лл
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