let 終點(diǎn)B =(x,y)
a //b
b = k(-2,3) ( k is a constant )
(x,y) -(1,2) = b = k(-2,3)
(x-1,y-2) =(-2k,3k)
=> x-1 = -2k and y-2 =3k
=> x= -2k+1 and y= 3k+2
B在坐標(biāo)軸上 => x= 0 or y=0
case 1:x=0
k= 1/2,y=7/2
B(0,7/2)
case 2:y=0
k= -2/3 ,x=7/3
B=(7/3,0)
ie
終點(diǎn)B= (0,7/2) or (7/3,0)