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  • 計(jì)算 2sin10+cos10+tan20sin10,

    計(jì)算 2sin10+cos10+tan20sin10,
    數(shù)學(xué)人氣:169 ℃時(shí)間:2020-07-09 23:45:52
    優(yōu)質(zhì)解答
    2sin20°+cos10°+tan20sin10°
    =2sin20°+cos10°+sin20sin10°/cos20°
    =2sin20°+(cos20°cos10°+sin20sin10°)/cos20°
    =2sin20°+cos(20°-10°)/cos20°
    =2sin20°+cos10°/cos20°
    =(2sin20°cos20°+cos10°)/cos20°
    =(sin40°+cos10°)/cos20°
    =(sin40°+sin80°)/cos20°
    =2sin[(40°+80°)/2]*cos[(40°-80°)/2]/cos20°
    =2sin60°*cos20°/cos20°
    =2*√3/2
    =√3
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