[(x-2)分之3x-2分之x]×x分之(x²-4)
=[2(x-2)分之6x-2(x-2)分之(x²-2x)]×x分之[(x+2)(x-2)]
=2(x-2)分之(4x-x²)×x分之[(x+2)(x-2)]
=2(x-2)分之[x(4-x)]×x分之[(x+2)(x-2)]
=2分之[(4-x)(x+2)]

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有新問(wèn)題請(qǐng)求助,謝謝!不好意思，應(yīng)該是(x-2分之3x-x+2分之x)乘以x分之x的平方-4,用兩種方法計(jì)算[(x-2)分之3x-(x+2)分之x]×x分之(x²-4)=[(x+2)(x-2)]分之[3x(x+2)-x(x-2)]×x分之[(x+2)(x-2)]=[(x+2)(x-2)]分之(2x²+8x)×x分之[(x+2)(x-2)]=[(x+2)(x-2)]分之[x(2x+8)]×x分之[(x+2)(x-2)]=2x+8 明白請(qǐng)采納，有疑問(wèn)請(qǐng)追問(wèn)！有新問(wèn)題請(qǐng)求助，謝謝!