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  • (1)x^2+3x+2分之x-1+2+x-x^2分之6-4-x^2分之10-x

    (1)x^2+3x+2分之x-1+2+x-x^2分之6-4-x^2分之10-x
    (2)x-y分之x乘以x+y分之y^2-x^4-y^4分之x^4y除以x^2+y^2分之x^2
    (3)當(dāng)x=-2時(shí),求x+1分之1-x^2-1分之x+3除以x^2-2x+1分之x^2+4x+3
    回答好了給你加100分
    數(shù)學(xué)人氣:777 ℃時(shí)間:2020-06-25 04:10:59
    優(yōu)質(zhì)解答
    x^2+3x+2分之x-1+2+x-x^2分之6-4-x^2分之10-x
    =(x-1)/(x²+3x+2)+6/(2+x-x²)-(10-x)/(4-x²)
    =(x-1)/(x+1)(x+2)-6/(x-2)(x+1)-(x-10)/(x-2)(x+2)
    =[(x-1)(x-2)-6(x+2)-(x-10)(x+1)]/(x+1)(x+2)(x-2)
    =(x²-3x+2-6x-12-x²+9x+10)/(x+1)(x+2)(x-2)
    =0/(x+1)(x+2)(x-2)
    =0
    (2)x-y分之x乘以x+y分之y^2-x^4-y^4分之x^4y除以x^2+y^2分之x^2
    =x/(x-y)*y²/(x+y)*(x⁴y)/(x⁴-y⁴)÷x²/(x²+y²)
    =x^5y³/[(x²-y²)(x²-y²)(x²+y²)]÷x²/(x²+y²)
    =x³y³/(x²-y²)²
    (3)當(dāng)x=-2時(shí),求x+1分之1-x^2-1分之x+3除以x^2-2x+1分之x^2+4x+3
    x+1分之1-x^2-1分之x+3除以x^2-2x+1分之x^2+4x+3
    =1/(x+1)-(x+3)/(x²-1)÷(x²+4x+3)/(x²-2x+1)
    =1/(x+1)-(x+3)/(x-1)(x+1)÷(x+1)(x+3)/(x-1)²
    =1/(x+1)-1/(x+1)²
    =(x+1-1)/(x+1)²
    =x/(x+1)²
    =-2/(-2+1)²
    =-2/1
    =-2
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