1）The sum of the area s of two circles is 65pi square feet.The length of a radius of the larger circle is one foot less
1）The sum of the area s of two circles is 65pi square feet.The length of a radius of the larger circle is one foot less than twice the length of the radius of the smaller circle.Find the length of a radius of each circle.
2)
The combined area of a square and a rectangle is 64 square centimeters.The width of the rectangle is 2 cm more than the length of a side of the square and the length of the rectangle is 2 cm more than its width.Find the dimensions of the square and the rectangle.
3)
The Ortegas have an apple orchard that contains 90 trees.The number of trees in each row is 3 more that twice the number of rows.Find the number of rows and the number of trees per row?
2)
The combined area of a square and a rectangle is 64 square centimeters.The width of the rectangle is 2 cm more than the length of a side of the square and the length of the rectangle is 2 cm more than its width.Find the dimensions of the square and the rectangle.
3)
The Ortegas have an apple orchard that contains 90 trees.The number of trees in each row is 3 more that twice the number of rows.Find the number of rows and the number of trees per row?
數(shù)學(xué)人氣：260 ℃時間：2020-04-16 06:24:27
優(yōu)質(zhì)解答
1、大圓小圓面積總和是65,大圓半徑比小圓半徑的2倍少1,求每個圓半徑.設(shè)小圓半徑為r,大圓半徑為2r-1,則 πr^2+π(2r-1)^2=65解出r后再求2r-1即可2、正方形和矩形面積之和為64.長方形的寬比正方形邊長大2,長方形的長比...
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