設HCl為xg,NaCl為yg
Na2CO3+2HCl==2NaCl+CO2+H2O
106g 73g 117g 44g
10.6g x y z
有106/10.6=73/x
得到x=7.3g
質(zhì)量分數(shù)是7.3/100*100%=7.3%
有106/10.6=117/y
y=11.7g
生成Co2的質(zhì)量是z=4.4g
溶液的質(zhì)量：100+10.6-4.4=106.2g
所以質(zhì)量分數(shù)=11.7/106.2=11%再幫一個忙！5.6gFe與200g鹽酸恰好完全反應。求（1）鹽酸中溶質(zhì)的質(zhì)量分數(shù)（2）反應后所得溶液中溶質(zhì)的質(zhì)量分數(shù)。Fe+2HCl==FeCl2+H2 5673 127 2 5.6x y z 得到：x=7.3g 質(zhì)量分數(shù)：7.3/200=3.65%FeCl2的質(zhì)量=12.7g 溶液的質(zhì)量=5.6+200-0.2=205.4g 質(zhì)量分數(shù)=12.7/205.4=6.2%記得追加些分數(shù)哦！哈哈