②當a≠0時,不等式ax2-(3a+2)x+6≤0可化為(ax-2 )(x-3)≤0(*).
當a<0時,(*)不等式化為(x-
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當0<a<
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當
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{x|
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綜上可知:當a=0時,原不等式的解集為{x|x≥3};
當a<0時,原不等式的解集為{x|x≤
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當a=
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當
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