已知二次函數(shù)y=-x2+2x+m2-1/2. (1)確定該函數(shù)圖象的頂點在第幾象限; (2)如果該函數(shù)的圖象經(jīng)過原點,求它的頂點坐標.
已知二次函數(shù)y=-x
2+2x+m
2-
.
(1)確定該函數(shù)圖象的頂點在第幾象限;
(2)如果該函數(shù)的圖象經(jīng)過原點,求它的頂點坐標.
數(shù)學人氣:185 ℃時間:2019-10-19 05:30:30
優(yōu)質(zhì)解答
(6)∵y=-x
2+2x+m
2-
=-(x
2-2x)+m
2-
=-(x-6)
2+m
2+
,
∴拋物線的頂點坐標為(6,m
2+
),在第6象限;
(2)∵拋物線經(jīng)過原點,
∴m
2-
=0,
∴m
2=
,
∴m
2+
=6,
∴頂點坐標為(6,6).
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