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  • 1、(1)計(jì)算{(3-x)/(x-2)}/(x-2-(13-4x)/(x-2)) (2) {1+4/(a-2)(a-4+4/a)-3}/(1/a²-1)

    1、(1)計(jì)算{(3-x)/(x-2)}/(x-2-(13-4x)/(x-2)) (2) {1+4/(a-2)(a-4+4/a)-3}/(1/a²-1)
    數(shù)學(xué)人氣:610 ℃時(shí)間:2020-02-06 05:54:07
    優(yōu)質(zhì)解答
     (1){(3-x)/(x-2)}/(x-2-(13-4x)/(x-2))
      ={(3-x)/(x-2)}/{(x-2)*(x-2)-(13-4x)/(x-2)
      ={(3-x)/(x-2)}/{((x²-4x+4)-(13-4x))/(x-2}
      ={(3-x)/(x-2)}/{(x²-4x+4-13+4x)/(x-2}
      ={(3-x)/(x-2)}/{(x²-9)/(x-2)}
      ={(3-x)/(x-2)}/{(x-3)*(x+3)/(x-2)}
      =(3-x)/(x-2)*(x-2)/(x-3)/(x+3)
      =-(x-3)/(x-3)/(x+3)
      =-1/(x+3)
     (2) {1+4/(a-2)(a-4+4/a)-3}/(1/a²-1)
      = {1+4/(a-2)((a-2)-2/a(a-2))-3}/{(1/a-1)(1/a+1)}
      =(1+4-2/a-3)/{(1/a-1)(1/a+1)}
      =(2-2/a)/{(1/a-1)(1/a+1)}
      =2(1-1/a)/{-(1-1/a)(1/a+1)}
      =-2/(1/a+1)
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