1.原式=(x²/x+1)÷(x²-2/x²-1)=[x²(x-1)]/(x²-2)
代入x=根號2+1得原式=【(3+2倍根號2)*根號2】/(1+2倍根號2)
=(8+5倍根號2)/7.
2.原式=[(x²-x)/(x-2)]÷[(x-1)²/(x-2)]
=x/(x-1)
代入得原式=(根號2+1)/根號2
=(2+根號2)/2.
3.原式=3-1/(a+1)-1/(b+1)-1/(c+1)
=3-(y+z)/(x+y+z)-(x+z)/(x+y+z)-(x+y)/(x+y+z)
=3-2=1.
希望對你有幫助.