x^2+3x-8=0
x=(-3+√9+4*1*8)/2=(-3+√41)/2
或x=(-3-√9+4*1*8)/2=(-3-√41)/2
x-2分之1 乘 x+1分之x2-4x+4 減 x+2分之1
=1/(x-2) * (x^2-4x+4)/(x+1) -1/(x+2)
= (x-2)^2/(x+1)(x-2) -1/(x+2)
= (x-2)/(x+1) -1/(x+2)
= ((x-2)(x+2)-(x+1)) /(x+1)(x+2)
= (x^2-4-x-1) /(x^2+3x+2)
= (x^2-x-5) /(x^2+3x+2)
= (x^2-x-5) /(x^2+3x+2)
= (8-3x-x-5) /(8+2)
= (3-4x) /10
當(dāng)x=(-3+√41)/2時(shí)
上式=(3-4*(-3+√41)/2) /10
?。?-3+6-2√41)/10
=(3-2√41)/10
當(dāng)x=(-3-√41)/2時(shí)
上式=(3-4*(-3-√41)/2) /10
?。?-3+6+2√41)/10
?。?3+2√41)/10考試題這么難算?考試時(shí)候耗時(shí)太長(zhǎng)了吧。
x2+3x-8=0 求 x-2分之1 乘 x+1分之x2-4x+4 減 x+2分之1
x2+3x-8=0 求 x-2分之1 乘 x+1分之x2-4x+4 減 x+2分之1
數(shù)學(xué)人氣:732 ℃時(shí)間:2020-07-01 11:47:04
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