做功(題目是英語的)..能幫的麻煩進(jìn)來解答
做功(題目是英語的)..能幫的麻煩進(jìn)來解答
A water skier is pulled by a string and slides on an inclined platform at a uniform speed of 10 ms^-1.The tension in the string is 375N.Assume the tension is the string is parallel to the displacement of the skier.
(a)How much work has the tension done on the water skier for 1s?
(b)How much kinetic energy does the skier gain 1s?explain briefly.
在 題(b) ..可以用中文...還有一個問題就是 如果 力F 對一個物體 做功 ...那個物體的動能一定會起 增加或減少...因?yàn)樽龉Φ亩x是 The amount of energy transferred in such process is called Work
A water skier is pulled by a string and slides on an inclined platform at a uniform speed of 10 ms^-1.The tension in the string is 375N.Assume the tension is the string is parallel to the displacement of the skier.
(a)How much work has the tension done on the water skier for 1s?
(b)How much kinetic energy does the skier gain 1s?explain briefly.
在 題(b) ..可以用中文...還有一個問題就是 如果 力F 對一個物體 做功 ...那個物體的動能一定會起 增加或減少...因?yàn)樽龉Φ亩x是 The amount of energy transferred in such process is called Work
英語人氣：509 ℃時間：2020-04-15 01:01:23
優(yōu)質(zhì)解答
(1) Work is defined as W = F.S cos(theta) since theta = 0 (Ok,you could argue that it could as well be 180,but it is just not commonly seen.),hence W = 375 * 10m/s *1s * 1 = 3750 J(2).Since the water ...
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