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  • 已知x=√2-1,求x^5-2x^3+6x^2-7x+2的值

    已知x=√2-1,求x^5-2x^3+6x^2-7x+2的值
    數(shù)學(xué)人氣:421 ℃時間:2020-01-28 08:47:26
    優(yōu)質(zhì)解答
    x=√2-1
    x^2=3-2√2
    x^5-2x^3+6x^2-7x+2
    =x^5-2x^3+x+6x^2-8x+2
    =x(x^4-2x^2+1)+6x^2-8x+2
    =x(x^2-1)^2+6x^2-8x+2
    =x(3-2√2-1)^2+6x^2-8x+2
    =(√2-1)(2-2√2)^2+6x^2-12x+6+4x-4
    =4(√2-1)(√2-1)^2+6(x-1)^2+4x-4
    =4(√2-1)(√2-1)^2+6(√2-1-1)^2+4x-4
    =4(√2-1)(3-2√2)+6(√2-2)^2+4x-4
    =4(√2-1)(3-2√2)+6(4-4√2)+4x-4
    =4(3√2-4-3+2√2)+6(4-4√2)+4(√2-1)-4
    =4(5√2-7)+6(4-4√2)+4√2-4-4
    =20√2-28+24-24√2+4√2-8
    =20√2-24√2+4√2+24-28-8
    =-12
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