解析：∵函數(shù)y=|x^2-x-6|=|(x-1/2)^2-25/4|
∴當(dāng)(x-1/2)^2-25/4=0==>x1=-2,x2=3
即當(dāng)x1=-2,x2=3時,函數(shù)y=0
當(dāng)x1≠-2,x2≠3時,函數(shù)y>0
當(dāng)x＞0時，y=（x-0.5）2+25/4 當(dāng)x≤0時 y=（x+1/2）2+25/4 不對！應(yīng)該為：∵函數(shù)y=|x^2-x-6|=|(x-1/2)^2-25/4|當(dāng)(x-1/2)^2>25/4，即x<-2或x>3時，y=(x-1/2)^2-25/4當(dāng)(x-1/2)^2<=25/4，即-2<=x<=3時，y=25/4-(x-1/2)^2