y=lg(x-√(x^2-a^2))的導(dǎo)數(shù),答案是y'=-1/√(x^2-a^2)lge,
y=lg(x-√(x^2-a^2))的導(dǎo)數(shù),答案是y'=-1/√(x^2-a^2)lge,
數(shù)學(xué)人氣:288 ℃時(shí)間:2020-05-31 14:04:31
優(yōu)質(zhì)解答
答案錯(cuò)了吧!y'=(1-x/√(x^2-a^2))/(x--√(x^2-a^2))ln10=-1/√(x^2-a^2)ln10你怎么算的?過程能再詳細(xì)點(diǎn)么?這不就是復(fù)合函數(shù)嗎?相當(dāng)于y=lgu,u=x-√(x^2-a^2),那么y'=(1/uln10)u'(之所以乘以u'是因?yàn)閡是x的函數(shù)),又u'=1-2x/2√(x^2-a^2),y'=[1/(x-√(x^2-a^2))ln10][1-2x/2√(x^2-a^2)]=-1/√(x^2-a^2)ln10
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