(1)他行走時(shí)對(duì)地的接觸面積為S1=150cm2=0.015m2,
∵p=
F |
S |
∴行走時(shí)對(duì)地的壓強(qiáng)p1=
F |
S1 |
588N |
0.015m2 |
(2)站立時(shí)對(duì)地的接觸面積為S2=2S1=2×150cm2=0.03m2,
∵p=
F |
S |
∴站立時(shí)對(duì)地的壓強(qiáng)p2=
F |
S2 |
588N |
0.03m2 |
故答案為:39200;19600.
F |
S |
F |
S1 |
588N |
0.015m2 |
F |
S |
F |
S2 |
588N |
0.03m2 |