滑輪組對(duì)物體的拉力F=G-F浮=1.4×104N-2×103N=1.2×104N,
物體上升速度v=
s |
t |
1m |
2s |
拉力移動(dòng)速度vC=
1 |
2 |
1 |
2 |
∵P=
W |
t |
Fs |
t |
∴繩端C處的拉力FC=
P |
vC |
7500W |
0.25m/s |
∵FC=2F+G動(dòng),
∴動(dòng)滑輪重G動(dòng)=FC-2F=30000N-2×1.2×104N=6000N,
當(dāng)貨物A完全出水后,繩端C處的拉力FC′=2G+G動(dòng)=2×1.4×104N+6000N=3.4×104N,
滑輪組的機(jī)械效率:
η=
W有用 |
W總 |
Gh | ||
F
|
2G |
FC′ |
2×1.4×104N |
3.4×104N |
故答案為:82.