∵p=
F |
S |
∴磚A對(duì)B的壓力:
F=pS=1500Pa×(L-
L |
3 |
磚的重力G=F=1000Ld,
B磚對(duì)地面的壓力F′=2G=1000Ld×2=2000Ld,
B磚對(duì)地面的壓強(qiáng)pB=
F′ |
S′ |
2000Ld |
Ld |
(2)∵G=mg,
∴磚的質(zhì)量m=
G |
g |
1000LdN |
10N/kg |
磚的密度ρ=
m |
V |
100Ldkg |
Ld×0.05m3 |
故答案為:2000;2000kg/m3.
1 |
3 |
F |
S |
L |
3 |
F′ |
S′ |
2000Ld |
Ld |
G |
g |
1000LdN |
10N/kg |
m |
V |
100Ldkg |
Ld×0.05m3 |