若Al完全反應(yīng),需要23/27*3*35.5=90.7g的Cl2,說(shuō)明Al過(guò)量,而Cl完全反應(yīng)
所以,Cl2完全反應(yīng),生成28/(3*71)*2*(27+3*35.5)=35.1g2Al(s)+3Cl2(g)→2AlCl3(s) 3 2 28/(35.5*2) x然后求出xmol的AlCl3 然后再求它的質(zhì)量嗎？對(duì)的，就是這個(gè)意思。
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:
2Al(s)+3Cl2(g)→2AlCl3(s)
What is the maximum mass of aluminum chloride that can be formed when reacting 23.0g of aluminum with 28.0g of chlorine?
Express your answer to three significant figures and include the appropriate units.
我算的是23.4g 但是不對(duì)
2Al(s)+3Cl2(g)→2AlCl3(s)
What is the maximum mass of aluminum chloride that can be formed when reacting 23.0g of aluminum with 28.0g of chlorine?
Express your answer to three significant figures and include the appropriate units.
我算的是23.4g 但是不對(duì)
英語(yǔ)人氣：771 ℃時(shí)間：2020-04-04 07:23:50
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