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  • (10-7/55×1)+(9-7/55×1)+(8-7/55×1)+.+(1-7/55×1)怎么簡(jiǎn)算?

    (10-7/55×1)+(9-7/55×1)+(8-7/55×1)+.+(1-7/55×1)怎么簡(jiǎn)算?
    對(duì)不起,我打錯(cuò)了 應(yīng)該是:(10-7/55×1)+(9-7/55×2)+(8-7/55×3)+......+(1-7/55×10)怎么簡(jiǎn)算?
    數(shù)學(xué)人氣:263 ℃時(shí)間:2020-03-26 06:35:40
    優(yōu)質(zhì)解答
    (10-7/55×1)+(9-7/55×1)+(8-7/55×1)+.+(1-7/55×1)
    =(10+9+8+···1)-7/55×1×10
    =(10+1)×10/2-14/11
    =55-14/11
    =55-1又3/11
    =(54-1)+(1-3/11)
    =53+8/11
    =53又8/11看不懂。。。。。。。。。。。。把式子拆開(kāi)看,每個(gè)括號(hào)前的整數(shù)分別相加,然后減去10個(gè)7/55×1。打錯(cuò)了 請(qǐng)你重新寫(xiě)一下把式子拆開(kāi)看,每個(gè)括號(hào)前的整數(shù)分別相加,然后減去(1+2+3+···10)個(gè)7/55×1。(10-7/55×1)+(9-7/55×2)+(8-7/55×3)+......+(1-7/55×10)=(10+9+8+···1)-7/55×(1+2+3+···10)=(10+1)×10/2-7/55×(10+1)×10/2=55-7/55×55=55-7=48
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