先裂項
f(z)=z/(z＋1)(z＋2)=-1/(1+z)+2/(2+z)
再根據(jù)需要變項
f(z)=-1/(3+z-2)+2/(4+z-2)=(-1/3){1/[1-[(-1)(z-2)/3]}+(1/2){1/[1-[(-1)(z-2)/4]}
再展開,z-2的絕對值小于3(因為-1是奇點)
f(z)=sigma{(-1/3)[(-1)(z-2)/3]^n}+(1/2)[(-1)(z-2)/4]^n}
sigma是求和號,從n=0到無窮